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Some classical inequalities and their applications

Authors:
  • Isparta University of Applied Sciences

Abstract

In this paper, we define analogies of classical H?lder-McCarthy and Young type inequalities in terms of the Berezin symbols of operators on a reproducing kernel Hilbert space H = H (?). These inequalities are applied in proving of some new inequalities for the Berezin number of operators. We also define quasi-paranormal and absolute-k-quasi paranormal operators and study their properties by using the Berezin symbols.
Filomat 35:7 (2021), 2165–2173
https://doi.org/10.2298/FIL2107165H
Published by Faculty of Sciences and Mathematics,
University of Niˇ
s, Serbia
Available at: http://www.pmf.ni.ac.rs/filomat
Some Classical Inequalities and their Applications
Mualla Birg ¨ul Hubana, Mehmet G ¨urdalb, Havva Tilkib
aIsparta University of Applied Sciences, Isparta, Turkey
bSuleyman Demirel University, Department of Mathematics, 32260, Isparta, Turkey
Abstract. In this paper, we define analogies of classical H¨
older-McCarthy and Young type inequalities
in terms of the Berezin symbols of operators on a reproducing kernel Hilbert space H=H().These
inequalities are applied in proving of some new inequalities for the Berezin number of operators. We also
define quasi-paranormal and absolute-k-quasi paranormal operators and study their properties by using
the Berezin symbols.
1. Introduction
Let H=H() be a Hilbert space of complex-valued functions on some set such that ff(λ)is a
continuous functional (evaluation functional) for any λin . Then, according to the Riesz’s representation
theorem there exists uniquely kλ∈ H such that
f(λ)=f,kλ
for all f∈ H . The function kλ(z), λ ,is called the reproducing kernel of the space H,and b
kλ:=kλ
kkλk
is called the normalized reproducing kernel in H(see [2]). The space Hwith the reproducing kernels
kλ, λ ,is called reproducing kernel Hilbert space (RKHS). For a bounded linear operator A(i.e., for
A∈ B(H), the Banach algebra of all bounded linear operators on H) its Berezin symbol e
Ais defined by
(Berezin [6, 7])
e
A(λ) :=DA
b
kλ,b
kλE, λ .
The Berezin number ber (A)of operator Ais the following number:
ber (A):=sup
λe
A(λ).
2010 Mathematics Subject Classification. Primary 47A63; Secondary 26D15, 47B10
Keywords. Reproducing kernel Hilbert space, Berezin symbol, Berezin number, quasi-paranormal operator, H ¨
older-McCarthy
type inequality, Young type inequality
Received: 07 July 2020; Accepted: 20 December 2020
Communicated by Fuad Kittaneh
This paper was supported by T ¨
UBA through Young Scientist Award Program (T ¨
UBA-GEBIP/2015).
Email addresses: muallahuban@isparta.edu.tr (Mualla Birg ¨
ul Huban), gurdalmehmet@sdu.edu.tr (Mehmet G ¨
urdal),
havvatilki32@gmail.com (Havva Tilki)
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2166
Since e
A(λ)kAk(by the Cauchy-Schwarz inequality) for all λ,the Berezin number is a finite number
and ber (A)kAk.Recall that
W(A):=hAx,xi:x∈ H and kxk=1
is the numerical range of operator Aand
w(A):=sup |hAx,xi| :x∈ H and kxk=1
=sup nµ:µW(A)o
is the numerical radius of A(for more information, see [1, 20–22]). It is well known that
Ber (A)W(A)and ber (A)w(A)
for any A∈ B(H).More information about ber (A)and relations between ber (A),w(A)and kAkcan be
found in Karaev [16, 18], and also in [3–5, 9–15, 17, 19, 23–25].
In this paper, we will use some known operator inequalities to prove some new inequalities for the
Berezin number of operators acting on the RKHS H=H().Some other related questions also will be
studied. In general, the present paper is motivated by the paper of Garayev [16], where the McCarthy,
H¨
older-McCarthy and Kantorovich operator inequalities were extensively used to get some new inequalities
for the Berezin number of operators and their powers. Recall that for any positive operator A(i.e., hAx,xi0
for any x∈ H, shortly A0), there exists a unique positive operator Rsuch that R2=A(denoted by R=A1
2).
An operator T∈ B(H) can be decomposed into T=UP,where Uis a partial isometry and P=|T|:=(TT)1
2
(moduli of operator T) with ker (T)=ker (P)and the last condition uniquely determines Uand Pof the
polar decomposition T=UP (see Furuta [8]). In general, we will refer to the book of Furuta [8] for main
definitions and notations.
2. H ¨older-McCarthy Type Inequalities and Berezin number
In this section, by using the H¨
older-McCarthy inequality, we prove some inequalities for the Berezin
number of some operators on the RKHS H.
Theorem 2.1. Let A ∈ B(H)be a positive operator. Then :
1) ber (Aµ)ber (A)µfor any µ > 1.
2) ber (Aµ)ber (A)µfor any µ[0,1].
3) If A is invertible, then ber (Aµ)ber (A)µfor any µ < 0.
Proof. First we prove 2). Indeed, assume that 2) holds for some α,β[0,1].Then we only have to prove 2) holds for
α+β
2[0,1]by continuity of an operator. In fact, we have for any λthat
Aα+β
2b
kλ,b
kλ
2
=Aα
2b
kλ,Aβ
2b
kλ
2
(by Cauchy-Schwarz inequality)
DAα
b
kλ,b
kλEDAβ
b
kλ,b
kλE(by assumption)
DA
b
kλ,b
kλEα+β,
so that g
Aα+β
2(λ)e
A(λ)α+β
2holds for α+β
2[0,1].This implies the desired inequality ber (Aµ)ber (A)µfor any
µ[0,1].
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2167
1) Let µ > 1.Then 1
µ[0,1].For any λ
DA
b
kλ,b
kλE=DAµ1
µb
kλ,b
kλE
DAµ
b
kλ,b
kλE1
µby 2),
hence DAµ
b
kλ,b
kλE>DA
b
kλ,b
kλEµfor any µ > 1,which shows that ber (Aµ)>ber (A)µfor any µ > 1, as desired.
3) Since A is invertible, we have the following for any λthat
1=
b
kλ
4=DA1
2b
kλ,A1
2b
kλE
2
A1
2b
kλ
2
A1
2b
kλ
2
=DA
b
kλ,b
kλEDA1
b
kλ,b
kλE
=e
A(λ)g
A1(λ),
and hence
1e
A(λ)g
A1(λ)for any λ,(1)
which gives us
ber (A)ber A1>1,
or equivalently
ber A1>ber (A)1.
Case: µ(−∞,1).Then we have the following for any λthat
DAµ
b
kλ,b
kλE=DA|µ|b
kλ,b
kλE
>DA1
b
kλ,b
kλEµ(by 1) since µ>1)
>DA
b
kλ,b
kλE|µ|(by (1))
=DA
b
kλ,b
kλEµ
which implies that ber (Aµ)>ber (A)µ, as desired.
Case: µ[1,0).For every λwe have
e
Aµ(λ)=DAµ
b
kλ,b
kλE=DA|µ|b
kλ,b
kλE
>DA|µ|b
kλ,b
kλE1(by (1))
>DA
b
kλ,b
kλE|µ|=DA
b
kλ,b
kλEµ=e
A(λ)µ,
and the last inequality follows by 2) since µ[0,1]and taking inverses of both sides. The theorem is proved.
Next result proves the equivalence of H¨
older-McCarthy type inequality and Young type inequality.
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2168
Theorem 2.2. For a positive operator A ∈ B(H)and µ[0,1]the following inequalities are equivalent:
older-McCarthy type inequality:
e
A(λ)µ>f
Aµ(λ)for all λ.(2)
Young type inequality:
µA+Iµ>f
Aµ.(3)
Proof. Let us define a scalar function
f(t):=µt+1µtµ
for positive numbers tand µ[0,1]. Then it is easy to see that f(t)is a nonnegative convex function with
the minimum value f(1)=0,so we have
µa+1µ>aµ(4)
for positive aand µ[0,1].
(2) (3).Replacing aby e
A(λ)>0 and µ[0,1]in (4),we obtain
µe
A(λ)+1µ>A(λ)µ>f
Aµ(λ)by (2),
so we have (3).
(3) (2).We may assume µ(0,1].In (3),replace Aby k1
µAfor a positive number k,then
µk1
µe
A(λ)+1µ>kf
Aµ(λ)(5)
for λby (3).We put k=e
A(λ)µin (5) if e
A(λ),0,then we have
µe
A(λ)1e
A(λ)+1µ>e
A(λ)µf
Aµ(λ),
that is A(λ)µ>f
Aµ(λ)for all λand we get (2).If e
A(λ)=0,then it means that A1
2b
kλ=0,so Aµ
b
kλ=0 for
µ(0,1]by the induction and continuity of A, and thus we have (2).The theorem is proved.
Proposition 2.3. Let A ∈ B(H)be a positive invertible operator and B ∈ B(H)be an invertible operator. Then for
any real number µ, we have
ber (BAB)µ=ber BA1
2A1
2BBA1
2µ1A1
2B.(6)
Proof. Let BA1
2=UP be the polar decomposition of BA 1
2, where Uis unitary and P=BA 1
2.Then it is easy
to see that:
(BAB)µ=UP2Uµ=BA 1
2P1P2µP1A1
2B
=BA1
2A1
2BBA1
2µ1A1
2B.
Now (6) is immediate from this equality.
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2169
3. Paranormal operators and related problems
Recall that an operator Aon a Hilbert space His called paranormal if
A2x
kAxk2for every unit vector
xH.
Definition 3.1. We will say that A is a quasi-paranormal operator on a RKHS H=H(),if
A2
b
kλ
A
b
kλ
2for
any λ.
Definition 3.2. An operator T belongs to class e
Aif g
T2g
|T|2.
Definition 3.3. For each k >0,an operator T is absolute-k-quasi-paranormal if
|T|kTb
kλ
Tb
kλ
k+1(7)
for every λ.
It follows from these definitions that:
(a) If Ais quasi-paranormal, then
ber A22ber |A|22;
(b) If Abelongs to class e
A, then
ber A2ber |A|2;
(c) If Ais absolute-k-quasi-paranormal, then
ber |A|kA2ber (|A|)k+1.
In this section, to prove some inequalities for the Berezin number of such operators, we need to other
properties of these operators.
Proposition 3.4. Every operator in e
Ais a quasi-paranormal operator on a RKHS.
Proof. Suppose Ae
A, i.e.,
g
A2g
|A|2.(8)
Then for every λ,we have g
A2(λ)g
|A|2(λ),and therefore it follows from the proof of Theorem 2.1
that
A2
b
kλ
2=DA2
b
kλ,A2
b
kλE=DA2A2
b
kλ,b
kλE
=A22b
kλ,b
kλ
DA2b
kλ,b
kλE2(see the proof of Theorem 2.1, 1))
D|A|2b
kλ,b
kλE2(by (8))
=
A
b
kλ
4.
Hence
A2
b
kλ
A
b
kλ
2
for every λ,so that Ais quasi-paranormal, which proves the proposition.
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2170
Definition 3.5. For each k >0,we say that an operator A belongs to class e
A(k)if
A|A|2kA1
k+1
g
|A|2.
The proof of Theorem 2.1 allows us also prove the following.
Proposition 3.6. (a) Every quasi-paranormal operator on a RKHS H=H()is an absolute-k-quasi-paranormal
operator for k 1.
(b) For each k >0,every class e
A(k)operator is an absolute-k-quasi-paranormal operator.
Proof. (a) Suppose that Ais a quasi-paranormal operator on a RKHS H=H().Then, for any λand
k1,we have
|A|kA
b
kλ
2=D|A|2kA
b
kλ,A
b
kλE
D|A|2A
b
kλ,A
b
kλEk
A
b
kλ
2(1k)(see the proof of Theorem 2.1, 1))
=
A2
b
kλ
2k
A
b
kλ
2(1k)
A
b
kλ
4k
A
b
kλ
2(1k)(by quasi-paranormality of A)
A
b
kλ
2(k+1),
and hence
|A|kA
b
kλ
A
b
kλ
k+1
for all λand k1,so that Ais absolute-k-quasi-paranormal operator for k1.
(b) Let Ae
A(k)for k>0,that is
A|A|2kA1
k+1
g
|A|2for k>0.(9)
Then for any λ,
|A|kA
b
kλ
2=DA|A|2kA
b
kλ,b
kλE
A|A|2kA1
k+1b
kλ,b
kλk+1
D|A|2b
kλ,b
kλEk+1(by (9))
=
A
b
kλ
2(k+1),
from which
|A|kA
b
kλ
A
b
kλ
k+1for all λ,
so that Ais absolute-k-quasi-paranormal operator for k>0.This completes the proof.
As further extension of previous results, we prove the following result.
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2171
Theorem 3.7. Let A B (H()) be an absolute-k-quasi-paranormal operator for k >0.Then for every λ,
F(`)=
|A|`A
b
kλ
1
`+1
is increasing for ` > k>0,and the following inequality holds:
F(`)
A
b
kλ
,
i.e., A is absolute-`-quasi-paranormal operator for `k>0.
Proof. Assume that Ais an absolute-k-quasi-paranormal operator on H=H()for k>0,i.e.,
|A|kA
b
kλ
A
b
kλ
k+1(10)
for every λ.Clearly, (10)holds if and only if
F(k)=
|A|kA
b
kλ
1
k+1
A
b
kλ
for any λ.Then for every λand any `such that `k>0,we have
F(`)=
|A|`A
b
kλ
1
`+1=D|A|2`A
b
kλ,b
kλE1
2(`+1)
(D|A|2kA
b
kλ,A
b
kλE1
k
A
b
kλ
2(11
k))1
2(`+1)
(
A
b
kλ
2`(k+1)
k
A
b
kλ
2(11
k))1
2(`+1)
(by (10))
=
A
b
kλ
,
and hence
F(`)=
|A|`A
b
kλ
1
`+1
A
b
kλ
(11)
for every λand `k,so that Ais absolute-`-quasi-paranormal for `k>0.
Now we prove that, F(`)is increasing for `k>0.Indeed, for any λ,mand `such that
m`k>0,we have:
F(m)=
|A|mA
b
kλ
1
m+1=D|A|2mA
b
kλ,A
b
kλE1
2(m+1)
=(D|A|2`A
b
kλ,A
b
kλEm
`
A
b
kλ
2(1m
`))1
2(m+1)
=(
|A|`A
b
kλ
2m
`
A
b
kλ
2(1m
`))1
2(m+1)
(
|A|`A
b
kλ
2m
`
|A|`A
b
kλ
2
`+1(1m
`))1
2(m+1)
(by (11))
=
|A|`A
b
kλ
1
`+1=F(`),
hence F(m)F(`),that is F(`)is increasing for `k>0.This proves the theorem.
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2172
Corollary 3.8. F(`)qber |A|2for `k>0.
The following lemma is well known (see, for instance, [8]).
Lemma 3.9. Let a and b be positive real numbers. Then,
aλbµλa+µb
holds for λ > 0and µ > 0such that λ+µ=1.
Our next result characterizes absolute-k-quasi-paranormal operators Aon the RKHS H=H().
Theorem 3.10. For each k >0,an operator A on His absolute-k-quasi-paranormal if and only if
A|A|2kA(k+1)αk|A|2+kαk+10
holds for all α > 0.
Proof. .Suppose that Ais absolute-k-quasi-paranormal for k>0,i.e.,
|A|kA
b
kλ
A
b
kλ
k+1(12)
for every λ.Inequality (12)holds if and only if
|A|kAkλ
1
k+1kkλkk
k+1kAkλk
for all λ,or equivalently
DA|A|2kAkλ,kλE1
k+1hkλ,kλik
k+1D|A|2kλ,kλE
for all λ.By Lemma 3.9, we have:
DA|A|2kAkλ,kλE1
k+1hkλ,kλik
k+1
=(1
αkDA|A|2kAkλ,kλE)1
k+1
{αhkλ,kλi} k
k+1(13)
1
k+1
1
αkDA|A|2kAkλ,kλE+k
k+1αhkλ,kλi
for all λand α > 0,so that (12)ensures the following inequality by (13):
1
k+1
1
αkDA|A|2kAkλ,kλE+k
k+1αhkλ,kλiD|A|2kλ,kλE(14)
for all λand α > 0.
Conversely, (14)implies (12)by putting α=hA|A|2kAkλ,kλi
hkλ,kλi1
k+1; in case DA|A|2kAkλ,kλE=0,let α0.
Hence (14)holds if and only if
A|A|2kA(k+1)αk|A|2+kαk+10
holds for all α > 0,which completes the proof of the theorem.
Since absolute-1-quasi-paranormal is quasi-paranormal, the following is immediate from Theorem 3.10.
M. B. Huban et al. /Filomat 35:7 (2021), 2165–2173 2173
Corollary 3.11. An operator A is quasi-paranormal if and only if
A2A22αAA+α20
holds for all α > 0.
Acknowledgement
The authors would like to express their hearty thanks to the anonymous reviewer for his/her valuable
comments.
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... For more recent results concerning Berezin radius inequalities for operators and other related results, we suggest [2,13,16,21,32,33]. ...
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