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Some Remarks on Regular Integers Modulo n

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Abstract

An integer $k$ is called regular (mod $n$) if there exists an integer $x$ such that $k^2x\equiv k$ (mod $n$). This holds true if and only if $k$ possesses a weak order (mod $n$), i.e., there is an integer $m\ge 1$ such that $k^{m+1} \equiv k$ (mod $n$). Let $\varrho(n)$ denote the number of regular integers (mod $n$) in the set $\{1,2,\ldots,n\}$. This is an analogue of Euler's $\phi$ function. We introduce the multidimensional generalization of $\varrho$, which is the analogue of Jordan's function. We establish identities for the power sums of regular integers (mod $n$) and for some other finite sums and products over regular integers (mod $n$), involving the Bernoulli polynomials, the Gamma function and the cyclotomic polynomials, among others. We also deduce an analogue of Menon's identity and investigate the maximal orders of certain related functions.
arXiv:1304.2699v2 [math.NT] 13 May 2015
Some remarks on regular integers modulo n
Br˘adut¸ Apostol and aszl´o T´oth
Filomat 29 (2015), no 4, 687–701
Available at http://www.pmf.ni.ac.rs/filomat
Abstract
An integer kis called regular (mod n) if there exists an integer xsuch that k2xk
(mod n). This holds true if and only if kpossesses a weak order (mod n), i.e., there is an
integer m1 such that km+1 k(mod n). Let ̺(n) denote the number of regular integers
(mod n) in the set {1,2,...,n}. This is an analogue of Euler’s φfunction. We introduce
the multidimensional generalization of ̺, which is the analogue of Jordan’s function. We
establish identities for the power sums of regular integers (mod n) and for some other finite
sums and products over regular integers (mod n), involving the Bernoulli polynomials, the
Gamma function and the cyclotomic polynomials, among others. We also deduce an analogue
of Menon’s identity and investigate the maximal orders of certain related functions.
2010 Mathematics Subject Classification: 11A25, 11B68, 11N37, 33B10, 33B15
Key Words and Phrases: regular integer (mod n), Euler’s totient function, Jordan’s function,
Ramanujan’s sum, unitary divisor, Bernoulli numbers and polynomials, Gamma function, finite
trigonometric sums and products, cyclotomic polynomial
1 Introduction
Throughout the paper we use the notations: N:= {1,2,...},N0:= {0,1,2,...},Zis the
set of integers, xis the integer part of x,1is the function given by 1(n) = 1 (nN), id is
the function given by id(n) = n(nN), φis Euler’s totient function, τ(n) is the number of
divisors of n,µis the M¨obius function, ω(n) stands for the number of prime factors of n, Λ is
the von Mangoldt function, κ(n) := Qp|npis the largest squarefree divisor of n,cn(t) are the
Ramanujan sums defined by cn(t) := P1kn,gcd(k,n)=1 exp(2πikt/n) (nN, t Z), ζis the
Riemann zeta function. Other notations will be fixed inside the paper.
Let nNand kZ. Then kis called regular (mod n) if there exists xZsuch that k2xk
(mod n). This holds true if and only if kpossesses a weak order (mod n), i.e., there is mN
such that km+1 k(mod n). Every kZis regular (mod 1). If n > 1 and its prime power
factorization is n=pν1
1···pνr
r, then kis regular (mod n) if and only if for every i∈ {1,...,r}
either pikor pνi
i|k. Also, kis regular (mod n) if and only if gcd(k, n) is a unitary divisor of n.
We recall that dis said to be a unitary divisor of nif d|nand gcd(d, n/d) = 1, notation d||n.
Note that if nis squarefree, then every kZis regular (mod n). See the papers [1,14,15,20]
for further discussion and properties of regular integers (mod n), and their connection with the
notion of regular elements of a ring in the sense of J. von Neumann.
1
An integer kis regular (mod n) if and only if k+nis regular (mod n). Therefore, it is
justified to consider the set
Regn:= {kN: 1 kn, k is regular (mod n)}
and the quantity ̺(n) := # Regn. For example, Reg12 ={1,3,4,5,7,8,9,11,12}and ̺(12) = 9.
If nis squarefree, then Regn={1,2,...,n}and ̺(n) = n. Note that 1, n Regnfor every
nN. The arithmetic function ̺is an analogue of Euler’s φfunction, it is multiplicative and
̺(pν) = φ(pν) + 1 = pνpν1+ 1 for every prime power pν(νN). Consequently,
̺(n) = X
d|| n
φ(d) (nN).(1)
See, e.g., [13] for general properties of unitary divisors, in particular the unitary convolution
of the arithmetic functions fand gdefined by (f×g)(n) = Pd|| nf(d)g(n/d). Here f×g
preserves the multiplicativity of the functions fand g. We refer to [20] for asymptotic properties
of the function ̺.
The function
cn(t) := X
kRegn
exp(2πikt/n) (nN, t Z),
representing an analogue of the Ramanujan sum cn(t) was investigated in the paper [8]. We
have
cn(t) = X
d|| n
cd(t) (nN, t Z).
It turns out that for every fixed tthe function n7→ cn(t) is multiplicative, cn(0) = ̺(n) and
cn(1) = µ(n) is the characteristic function of the squarefull integers n.
The gcd-sum function is defined by P(n) := Pn
k=1 gcd(k, n) = Pd|nd φ(n/d), see [22]. The
following analogue of the gcd-sum function was introduced in the paper [21]:
e
P(n) := X
kRegn
gcd(k, n).
One has
e
P(n) = X
d|| n
d φ(n/d) = nY
p|n21
p(nN),
the asymptotic properties of e
P(n) being investigated in [10,22,26,27].
In the present paper we discuss some further properties of the regular integers (mod n). We
first introduce the multidimensional generalization ̺r(rN) of the function ̺, which is the
analogue of the Jordan function φr, where φr(n) is defined as the number of ordered r-tuples
(k1,...,kr)∈ {1,...,n}rsuch that gcd(k1,...,kr) is prime to n(see, e.g., [13,18]). Then we
consider the sum S[reg]r(n) of r-th powers of the regular integers (mod n) belonging to Regn. In
the case rNwe deduce an exact formula for S[reg]r(n) involving the Bernoulli numbers Bm.
For a positive real number rwe derive an asymptotic formula for S[reg]r(n). We combine the
functions cn(t) and e
P(n) defined above and establish identities for sums, respectively products
over the integers in Regnconcerning the Bernoulli polynomials Bm(x), the Gamma function Γ,
the cyclotomic polynomials Φm(x) and certain trigonometric functions. We point out that for n
squarefree these identities reduce to the corresponding ones over {1,2,...,n}. We also deduce
an analogue of Menon’s identity and investigate the maximal orders of some related functions.
2
2 A generalization of the function ̺
For rNlet ̺r(n) be the number of ordered r-tuples (k1,...,kr)∈ {1,...,n}rsuch that
gcd(k1,...,kr) is regular (mod n). If r= 1, then ̺1=̺. The arithmetic function ̺ris
the analogue of the Jordan function φr, defined in the Introduction and verifying φr(n) =
nrQp|n(1 1/pr) (nN).
Proposition 2.1. i) For every r, n N,
̺r(n) = X
d|| n
φr(d).
ii) The function ̺ris multiplicative and for every prime power pν(νN),
̺r(pν) = ppr(ν1) + 1.
Proof. i) The integer gcd(k1,...,kr) is regular (mod n) if and only if gcd(gcd(k1,...,kr), n)||n,
that is gcd(k1,...,kr, n)||nand grouping the r-tuples (k1,...,kr) according to the values
gcd(k1,...,kr, n) = dwe deduce that
̺r(n) = X
(k1,...,kr)∈{1,...,n}r
gcd(k1,...,kr) regular (mod n)
1 = X
d|| nX
(k1,...,kr)∈{1,...,n}r
gcd(k1,...,kr,n)=d
1
=X
d|| nX
(1,...,ℓr)∈{1,...,n/d}r
gcd(1,...,ℓr,n/d)=1
1,
where the inner sum is φr(n/d), according to its definition.
ii) Follows at once by i).
More generally, for a fixed real number slet φs(n) = Pd|ndsµ(n/d) be the generalized
Jordan function and define ̺sby
̺s(n) = X
d|| n
φs(d) (nN).(2)
The functions φsand ̺s(which will be used in the next results of the paper) are multiplicative
and for every prime power pν(νN) one has φs(pν) = pps(ν1) and ̺s(pν) = pps(ν1) +1.
Note that φs(n) = nsQpν|| n(1 ps) and ̺s(n) = nsQpν|| n(pps+ 1).
Proposition 2.2. If s > 1is a real number, then
X
nx
̺s(n) = xs+1
s+ 1 Y
p11
ps+1 +p1
p(ps+1 1)+O(xs).(3)
Proof. We need the following asymptotics. Let s > 0 be fixed real number. Then uniformly for
real x > 1 and tN,
φs(x, t) := X
nx
gcd(n,t)=1
φs(n) = xs+1
(s+ 1)ζ(s+ 1) ·tsφ(t)
φs+1(t)+O(xs2ω(t)).(4)
3
To show (4) use the known estimate, valid for every fixed s > 0 and tN,
X
nx
gcd(n,t)=1
ns=xs+1
s+ 1 ·φ(t)
t+Oxs2ω(t).(5)
We obtain
φs(x, t) = X
de=nx
gcd(n,t)=1
µ(d)es=X
dx
gcd(d,t)=1
µ(d)X
ex/d
gcd(e,t)=1
es
=X
dx
gcd(d,t)=1
µ(d)(x/d)s+1
s+ 1 ·φ(t)
t+O(x/d)s2ω(t)
=xs+1
s+ 1 ·φ(t)
t
X
d=1
gcd(d,t)=1
µ(d)
ds+1 +O xs+1 X
d>x
1
ds+1 !+Oxs2ω(t),
giving (4). Now from (2) and (4),
X
nx
̺s(n) = X
de=nx
gcd(d,e)=1
φs(e) = X
dxX
ex/d
gcd(e,d)=1
φs(e) = X
dx
φs(x/d, d)
=xs+1
(s+ 1)ζ(s+ 1)
X
d=1
φ(d)
s+1(d)+O xs+1 X
d>x
φ(d)
s+1(d)!+O
xsX
dx
2ω(d)
ds
,
and for s > 1 this leads to (3).
Compare (3) to the corresponding formula for the Jordan function φs, i.e., to (4) with t= 1.
Remark 2.3. For the function ̺one has
X
nx
̺(n) = 1
2Y
p11
p2(p+ 1)x2+R(x),
where R(x) = O(xlog3x) can be obtained by the elementary arguments given above. This can
be improved into R(x) = O(xlog x) using analytic methods. See [20] for references.
3 A general scheme
In order to give exact formulas for certain sums and products over the regular integers (mod
n) we first present a simple result for a general sum over Regn, involving a weight function w
and an arithmetic function f. It would be possible to consider a more general sum, namely
over the ordered r-tuples (k1,...,kr)∈ {1,...,n}rsuch that gcd(k1,...,kr) is regular (mod n),
but we confine ourselves to the following result. See [24] for another similar scheme concerning
weighted gcd-sum functions.
4
Proposition 3.1. i) Let w:N2Cand f:NCbe arbitrary functions and consider the
sum
Rw,f (n) := X
kRegn
w(k, n)f(gcd(k, n)).
Then
Rw,f (n) = X
d|| n
f(d)
n/d
X
j=1
gcd(j,n/d)=1
w(dj, n) (nN).(6)
ii) Assume that there is a function g: (0,1] Csuch that w(k, n) = g(k/n)(1kn)
and let
G(n) =
n
X
k=1
gcd(k,n)=1
g(k/n) (nN).
Then
Rw,f (n) = X
d|| n
f(d)G(n/d) (nN).(7)
Proof. i) Using that kis regular (mod n) if and only if gcd(k, n)||nand grouping the terms
according to the values of gcd(k, n) = dand denoting k=dj we have at once
Rw,f (n) = X
d|| n
f(d)
n
X
k=1
gcd(k,n)=d
w(k, n) = X
d|| n
f(d)
n/d
X
j=1
gcd(j,n/d)=1
w(dj, n).
ii) Now
n/d
X
j=1
w(dj, n) =
n/d
X
j=1
g(j/(n/d)) = G(n/d).
Remark 3.2. For the function ggiven above let
G(n) :=
n
X
k=1
g(k/n).
Then we have
G(n) = X
d|n
µ(d)G(n/d) (nN).(8)
Indeed, as it is well known, G(n) = Pn
k=1 g(k/n)Pd|gcd(k,n)µ(d), giving (8).
5
4 Power sums of regular integers (mod n)
In this section we investigate the sum of r-th powers (rN) of the regular integers (mod
n). Let Bm(mN0) be the Bernoulli numbers defined by the exponential generating function
t
et1=
X
m=0
Bm
tm
m!.
Here B0= 1, B1=1/2, B2= 1/6, B4=1/30, Bm= 0 for every m3, modd and one
has the recurrence relation
Bm=
m
X
j=0 m
jBj(m2).(9)
It is well known that for every n, r N,
Sr(n) :=
n
X
k=1
kr=1
r+ 1
r
X
m=0
(1)mr+ 1
mBmnr+1m
=nr
2+1
r+ 1
r/2
X
m=0 r+ 1
2mB2mnr+12m.(10)
From here one obtains, using the same device as that given in Remark 3.2 that for every
n, r Nwith n2,
S[relpr]r(n) :=
n
X
k=1
gcd(k,n)=1
kr=nr
r+ 1
r/2
X
m=0 r+ 1
2mB2mφ12m(n),(11)
where φ12m(n) = n12mQp|n1p2m1. Formula (11) was given in [19]. Here we prove the
following result.
Proposition 4.1. For every n, r N,
S[reg]r(n) := X
kRegn
kr=nr
2+nr
r+ 1
r/2
X
m=0 r+ 1
2mB2m̺12m(n),(12)
where
̺12m(n) = n12mY
pν|| np(2m1)νp2m1+ 1
is the generalized ̺function, discussed in Section 2.
Proof. Applying (6) for w(k, n) = krand f=1we have
S[reg]r(n) = X
d|| n
n/d
X
j=1
gcd(j,n/d)=1
(dj)r=X
d|| n
drS[relpr]r(n/d).
6
Now by (11) we deduce
S[reg]r(n) = nr+X
d|| n
d<n
dr
(n/d)r
r+ 1
r/2
X
m=0 r+ 1
2mB2mφ12m(n/d)
=nr+nr
r+ 1
r/2
X
m=0 r+ 1
2mB2mX
d|| n
d<n
φ12m(n/d)
=nr+nr
r+ 1
r/2
X
m=0 r+ 1
2mB2mX
d|| n
d>1
φ12m(d)
=nrnr
r+ 1
r/2
X
m=0 r+ 1
2mB2m+nr
r+ 1
r/2
X
m=0 r+ 1
2mB2mX
d|| n
φ12m(d).
Here Pd|| nφ12m(n) = ̺12m(d) by (2). Also, by (9),
r/2
X
m=0 r+ 1
2mB2m=r+ 1
2
and this completes the proof.
For example, in the cases r= 1,2,3,4 we deduce that for every nN,
S[reg]1(n) = n(̺(n) + 1)
2,(13)
S[reg]2(n) = n2
2+n2̺(n)
3+n
6Y
pν|| n
(pνp+ 1) ,(14)
S[reg]3(n) = n3
2+n3̺(n)
4+n2
4Y
pν|| n
(pνp+ 1) ,
S[reg]4(n) = n4
2+n4̺(n)
5+n3
3Y
pν|| n
(pνp+ 1) n
30 Y
pν|| np3νp3+ 1.
The formula (13) was obtained in [20, Th. 3] and [3, Sec. 2], while (14) was given in a different
form in [3, Prop. 1]. Note that if nis squarefree, then (12) reduces to (10).
For a real number sconsider now the slightly more general sum
S[reg]s(n, x) := X
kx
kregular (mod n)
ks.
7
Proposition 4.2. Let s0be a fixed real number. Then uniformly for real x > 1and nN,
S[reg]s(n, x) = xs+1
s+ 1 ·̺(n)
n+Oxs3ω(n).
Proof. Similar to the proof of Proposition 3.1,
S[reg]s(n, x) = X
kx
gcd(k,n)|| n
ks=X
d|| n
dsX
jx/d
gcd(j,n/d)=1
js.
Now using the estimate (5) we deduce
S[reg]s(n, x) = X
d|| n
ds(x/d)s+1φ(n/d)
(s+ 1)(n/d)+O(x/d)s2ω(n/d)
=xs+1
(s+ 1)nX
d|| n
φ(n/d) + O
xsX
d|| n
2ω(n/d)
,
and using (1) the proof is complete.
5 Identities for other sums and products over regular integers
(mod n)
5.1 Sums involving Bernoulli polynomials
Let Bm(x) (mN0) be the Bernoulli polynomials defined by
text
et1=
X
m=0
Bm(x)tm
m!.
Here B0(x) = 1, B1(x) = x1/2, B2(x) = x2x+ 1/6, B3(x) = x33x2/2 + x/2,
Bm(0) = Bm(mN0) are the Bernoulli numbers already defined in Section 4and one has the
recurrence relation
Bm(x) =
m
X
j=0 m
jBjxmj(mN0).
It is well known (see, e.g., [5, Sect. 9.1]) that for every n, m N,m2,
Tm(n) :=
n
X
k=1
Bm(k/n) = Bm
nm1.(15)
Furthermore, applying (8) one obtains from (15) that for every n, m N,m2,
T[relpr]m(n) :=
n
X
k=1
gcd(k,n)=1
Bm(k/n) = Bmφ1m(n),(16)
8
where φ1m(n) = n1mQp|n1pm1. See [5, Sect. 9.9, Ex. 7]. We now show the validity of
the next formula:
Proposition 5.1.1 For every n, m N,m2,
T[reg]m(n) := X
kRegn
Bm(k/n) = Bm̺1m(n),(17)
where ̺1m(n) = n1mQpν|| np(m1)νpm1+ 1.
Proof. Choosing g(x) = Bm(x) and f=1we deduce from (7) by using (16) that
T[reg]m(n) = X
d|| n
T[relpr]m(d)
=BmX
d|| n
φ1m(d) = Bm̺1m(n),
according to (2).
Remark 5.1.2 In the case m= 1 a direct computation and (13) show that T[reg]1(n) = 1/2.
Also, (17) can be put in the form
n1
X
k=0
kregular (mod n)
Bm(k/n) = Bm̺1m(n),
which holds true for every n, m N, also for m= 1.
5.2 Sums involving gcd’s and the exp function
Consider in what follows the function
P[reg]f,t(n) := X
kRegn
f(gcd(k, n)) exp(2πikt/n) (nN, t Z),
where fis an arbitrary arithmetic function. For t= 0 and f(n) = n(nN) we reobtain the
function e
P(n) and for f=1we have cn(t), the analogue of the Ramanujan sums, both given in
the Introduction. We have
Proposition 5.2.1 For every fand every nNand tZ,
P[reg]f,t(n) = X
d|| n
f(d)cn/d(t).
If fis integer valued and multiplicative (in particular, if f= id), then n7→ P[reg]f ,t(n)also
has these properties.
9
Proof. Choosing g(x) = exp(2πitx) from (7) we deduce at once that
P[reg]f,t (n) = X
d|| n
f(d)
n/d
X
j=1
gcd(j,n/d)=1
exp(2πijt/(n/d)) = X
d|| n
f(d)cn/d(t).
For t= 1 and f= id this gives the multiplicative function
P[reg]id,1(n) = X
d|| n
(n/d),
not investigated in the literature, as far as we know. Here P[reg]id,1(pν) = p1 for every prime
pand P[reg]id,1(pν) = pνfor every prime power pνwith ν2.
Proposition 5.2.2 We have
X
nx
P[reg]id,1(n) = x2
2Y
p11
p2+1
p3+O(xlog2x).
Proof. Using (5) for s= 1 we deduce
X
nx
P[reg]id,1(n) = X
dx
µ(d)X
δx/d
gcd(δ,d)=1
δ
=X
dx
µ(d)φ(d)(x/d)2
2d+O((x/d)2ω(d))
=x2
2
X
d=1
µ(d)φ(d)
d3+O x2X
d>x
1
d2!+O
xX
dx
2ω(d)
d
,
giving the result.
5.3 An analogue of Menon’s identity
Our next result is the analogue of Menon’s identity ([12], see also [23])
n
X
k=1
gcd(k,n)=1
gcd(k1, n) = φ(n)τ(n) (nN).(18)
Proposition 5.3.1 For every nN,
X
kRegn
gcd(k1, n) = X
d|| n
φ(d)τ(d) = Y
pν|| npν1(p1)(ν+ 1) + 1.
10
Proof. Applying (6) for w(k, n) = gcd(k1, n) and f=1we deduce
Sn:= X
kRegn
gcd(k1, n) = X
d|| n
n/d
X
j=1
gcd(j,n/d)=1
gcd(dj 1, n)
=X
d|| n
n/d
X
j=1
gcd(j,n/d)=1
gcd(dj 1, n/d),
since gcd(dj 1, d) = 1 for every dand j. Now we use the identity
n
X
k=1
gcd(k,n)=1
gcd(ak 1, n) = φ(n)τ(n) (nN),
valid for every fixed aNwith gcd(a, n) = 1, see [23, Cor. 14] (for a= 1 this reduces to (18)).
Choose a=d. Since d||nwe have gcd(d, n/d) = 1 and obtain
Sn=X
d|| n
φ(n/d)τ(n/d) = X
d|| n
φ(d)τ(d).
5.4 Trigonometric sums
Further identities for sums over Regncan be derived. As examples, consider the following
known trigonometric identities. For every nN,n2,
n
X
k=1
cos2
n=n
2;
furthermore, for every nNodd number,
n
X
k=1
tan2
n=n2n;
and also for every nNodd,
n
X
k=1
tan4
n=1
3(n44n2+ 3n).
See, for example, [4] for a discussion and proofs of these identities. See [16, Appendix 3] for
other similar identities. By the approach given in Remark 3.2 we deduce that for every nN,
n
X
k=1
gcd(k,n)=1
cos2
n=φ(n) + µ(n)
2;
11
for every nNodd number,
n
X
k=1
gcd(k,n)=1
tan2
n=φ2(n)φ(n);
and for every nNodd,
n
X
k=1
gcd(k,n)=1
tan4
n=1
3(φ4(n)4φ2(n) + 3φ(n)).
This gives the next results. The proof is similar to the proofs given above.
Proposition 5.4.1 For every nN,
X
kRegn
cos2
n=̺(n) + µ(n)
2,
where µ(n) = Pd|| nµ(d)is the characteristic function of the squarefull integers n, given in the
Introduction.
Proposition 5.4.2 For every nNodd number,
X
kRegn
tan2
n=̺2(n)̺(n),
X
kRegn
tan4
n=1
3(̺4(n)4̺2(n) + 3̺(n)).
5.5 The product of numbers in Regn
It is known (see, e.g., [16, p. 197, Ex. 24]) that for every nN,
Q[relpr](n) :=
n
Y
k=1
gcd(k,n)=1
k=nφ(n)A(n),(19)
where
A(n) = Y
d|n
(d!/dd)µ(n/d).
We show that
Proposition 5.5.1 For every nN,
Q[reg](n) := Y
kRegn
k=n̺(n)Y
d|| n
A(d).
12
Proof. Choosing w(k, n) = log kand f=1in Proposition 3.1 we have
log Q[reg](n) = X
kRegn
log k=X
d|| n
n/d
X
j=1
gcd(j,n/d)=1
log(dj)
=X
d|| n
(φ(n/d) log d+ log Q[relpr](n/d))
=X
d|| n
(φ(d) log(n/d) + log Q[relpr](d))
= (log n)X
d|| n
φ(d)X
d|| n
φ(d) log d+X
d|| n
log Q[relpr](d).
Hence,
Q[reg](n) = n̺(n)Y
d|| n
Q[relpr](d)
dφ(d).
Now the result follows from the identity (19).
5.6 Products involving the Gamma function
Let Γ be the Gamma function defined for x > 0 by
Γ(x) = Z
0
ettx1dt.
It is well known that for every nN,
R(n) :=
n
Y
k=1
Γ(k/n) = (2π)(n1)/2
n,(20)
which is a consequence of Gauss’ multiplication formula. For the q-analogs of the Gamma and
Beta functions and the multiplication formula see the recent papers [6,7] published in this
journal. Furthermore, for every nN,n2,
R[relpr](n) :=
n
Y
k=1
gcd(k,n)=1
Γ(k/n) = (2π)φ(n)/2
exp(Λ(n)/2) ,(21)
see [17,11].
Proposition 5.6.1 For every nN,
R[reg](n) := Y
kRegn
Γ(k/n) = (2π)(̺(n)1)/2
pκ(n).(22)
13
Proof. Choosing g= log Γ and f=1in (7) and using (21) we deduce
log R[reg](n) = X
kRegn
log Γ(k/n) = X
d|| n
log R[relpr](d)
=X
d|| n
d>1log 2π
2φ(d)1
2Λ(d)
=X
d|| nlog 2π
2φ(d)1
2Λ(d)log 2π
2=log 2π
2(̺(n)1) 1
2X
d|| n
Λ(d),
where the last sum is log κ(n).
For squarefree n(22) reduces to (20).
5.7 Identities involving cyclotomic polynomials
Let Φn(x) (nN) stand for the cyclotomic polynomials (see, e.g., [9, Ch. 13]) defined by
Φn(x) =
n
Y
k=1
gcd(k,n)=1
(xexp(2πik/n)) .
Consider now the following analogue of the cyclotomic polynomials Φn(x):
Φ[reg]n(x) = Y
kRegn
(xexp(2πik/n)) .
The application of Proposition 3.1 gives the following result.
Proposition 5.7.1 For every nN,
Φ[reg]n(x) = Y
d|| n
Φd(x).
Here the degree of Φ[reg]n(x) is ̺(n). If nis squarefree, then Φ[reg]n(x) = xn1 and for
example, Φ[reg]12(x) = Φ1(x3(x4(x12 (x) = x9x6+x31.
It is well known that for every nN,n2,
U(n) :=
n
Y
k=1
gcd(k,n)=1
sin
n=Φn(1)
2φ(n),(23)
where
Φn(1) = (p, n =pν, ν 1,
1,otherwise, i.e., if ω(n)2,
and for n3,
V(n) :=
n
Y
k=1
gcd(k,n)=1
cos
n=Φn(1)
(4)φ(n)/2,(24)
14
where
Φn(1) =
2, n = 2 ν,
p, n = 2pν, p > 2 prime, ν 1,
1,otherwise.
For every nN,QkRegnsin(/n) = 0, since nRegn. This suggests to consider also the
modified products
U[regmod](n) :=
n1
Y
k=1
kregular (mod n)
sin
n,
V[regmod](n) :=
n1
Y
k=1
kregular (mod n)
cos
n.
We show that U[regmod](n) is nonzero for every n2. More precisely, define the modified
polynomials
Φ[regmod]n(x) = (x1)1Φ[reg]n(x) = Y
d|| n
d>1
Φd(x).
Here, for example, Φ[regmod]12(x) = Φ3(x4(x12(x) = x8+x7+x6+x2+x+ 1. All
of the polynomials Φ[regmod]n(x) have symmetric coefficients. By arguments similar to those
leading to the formulas (23) and (24) we obtain the following identities.
Proposition 5.7.2 For every nN,n2,
U[regmod](n) = Φ[regmod]n(1)
2̺(n)1=κ(n)
2̺(n)1,
and for every nN,n3odd,
V[regmod](n) = Φ[regmod]n(1)
(4)(̺(n)1)/2= (1/4)(̺(n)1)/2.
Note that ̺(n) is odd for every nNodd.
6 Maximal orders of certain functions
Let σ(n) be the sum of divisors of nand let ψ(n) = nQp|n(1 + 1/p) be the Dedekind
function. The following open problems were formulated in [2]: What are the maximal orders of
the functions ̺(n)σ(n) and ̺(n)ψ(n)?
The answer is the following:
Proposition 6.1.
lim sup
n→∞
̺(n)σ(n)
n2log log n= lim sup
n→∞
̺(n)ψ(n)
n2log log n=6
π2eγ,
where γis the Euler-Mascheroni constant.
15
Proof. Apply the following general result, see [25, Cor. 1]: If fis a nonnegative real-valued
multiplicative arithmetic function such that for each prime p,
i) ρ(p) := supν0f(pν)(1 1/p)1, and
ii) there is an exponent ep=po(1) Nsatisfying f(pep)1 + 1/p,
then
lim sup
n→∞
f(n)
log log n=eγY
p11
pρ(p).
Take f(n) = ̺(n)σ(n)/n2. Here f(p) = 1 + 1/p and f(pν) = 1 + 1/pν+ 1/pν+2 + 1/pν+3 +
...+ 1/p2ν<1 + 1/p for every prime pand every ν2. This shows that ρ(p) = 1 + 1/p and
obtain that
lim sup
n→∞
f(n)
log log n=eγY
p11
p2=6
π2eγ.
The proof is similar for the function g(n) = ̺(n)ψ(n)/n2. In fact, g(p) = f(p) = 1 + 1/p and
g(pν)f(pν) for every prime pand every ν2, therefore the result for g(n) follows from the
previous one.
Remark 6.2. Let σs(n) = Pd|nds. Then for every real s > 1,
lim sup
n→∞
̺s(n)σs(n)
n2s=ζ(s)
ζ(2s).
This follows by observing that for fs(n) = ̺s(n)σs(n)/n2s,fs(p) = 1 + 1/psand fs(pν) =
1 + 1/p+ 1/ps(ν+2) + 1/ps(ν+3) +...+ 1/p2<1 + 1/psfor every prime pand every ν2.
Hence, for every nN,
fs(n)Y
p|n1 + 1
ps<Y
p1 + 1
ps=ζ(s)
ζ(2s),
and the lim sup is attained for n=nk=Q1jkpjwith k→ ∞, where pjis the j-th prime.
7 Acknowledgement
L. T´oth gratefully acknowledges support from the Austrian Science Fund (FWF) under the
project Nr. M1376-N18.
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Br˘adut¸ Apostol
Pedagogic High School ”Spiru Haret”
Str. Timotei Cipariu, RO-620004 Foc¸sani, Romania
E-mail: apo brad@yahoo.com
aszl´o T´oth
Institute of Mathematics, Universit¨at f¨ur Bodenkultur
Gregor Mendel-Straße 33, A-1180 Vienna, Austria
and
Department of Mathematics, University of P´ecs
Ifj´us´ag u. 6, H-7624 P´ecs, Hungary
E-mail: ltoth@gamma.ttk.pte.hu
18
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