Question
Asked 31st Dec, 2021
  • Kozhnosys Pvt. Ltd.

How to make gaseous ppm solution?

Dear All,
Usually, we prepare the gaseous solution by taking a specific amount of N2 Gas in a Tedlar bag (e.g., 500 ml). By calculating the volume of solute (e.g., Toluene) by Density formula, we add it directly to the Tedlar bag. I would like to know whether I am doing the proper process to make the gaseous solution or not..!!
Kindly, please help
Thanking you in advance
(I am taking 5.7ul of Toluene in 500 ml of N2 Tedlar to make 10 ppm solution)

Most recent answer

Jaroslaw M Necki
AGH University of Science and Technology in Kraków
Julen Lur
, yes we can. In Tedlar bag you will have exactly what you will fill in. If you fill small amount of liquid or gas and than fill a lot of nitrogen than you exactly know what is the mole fraction inside.
Now, important part. You will use large syringe (like 500ml SGE), you will just calculate the amount of gas in reference to atmospheric pressure and lab temperature. If You want to be very precise, use precise measurement pressure gauge and try to keep everything in thermal equilibrium. Hope it is clear now.
Alternatively, you can use precise mass flow controller (MFC) to fill the bag with requested amount of nitrogen, helium or any other gas like zero air. MFC are offered widely. Be careful with any dead or unknown volumes behind MFC !
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All Answers (6)

Jaroslaw M Necki
AGH University of Science and Technology in Kraków
Dear Bhargav,
Basically ppm refers to molar fraction of one gas in mixture of gases. So you should count the number of molecules. Assuming the ideal gas law – when the pressure and temperature are constant, number of molecules is proportional to the volume, but assuming all is in gaseous state!
You didn’t specify the temperature of mixing but I assume it is the room temperature.
In that temperature toluene is a liquid so, if you take 5.7microliters than you have 54 micromole of toluene ( in 20deg Celsius it has a density of 0.87g/ml and molar mas of 94.115g/mol what gives 9.44 micromole/microliter).
Nitrogen is a gas and in normal condition its quite ideal and 0.5l makes 22.3 mmol = 22300 micromoles (one mole takes the 22.4dm3 volume).
If you mix these amount it will give you 2455ppm of toluene in nitrogen.
To check if toluene ha reached the equilibrium pressure lets look at its vapour pressure in 20deg C. The vapour pressure of toluene in 20deg C is 2.8kPa , for nitrogen it is 101kPa than equilibrated mixture will be close to 2.7% (if enough toluene to vaporise to this pressure volume and temp of the gases are equal), so definitely 2500ppm is below this value. If you provide 5.7 microliters to 500ml volume of tedlar bag – all of it will vaporise giving you 2455ppm gas mixture.
To get 10ppm use 0.024 microliters of liquid toluene and put it to 500ml (0.5l) of nitrogen. But due to surface adsorption effects it is better to keep it hot it or at least warm.
I’m not sure if you should add the correction of Van der Waals for molecular volume in case of toluene – check it.
Best regards,
Jarek
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Bhargav Raval
Kozhnosys Pvt. Ltd.
Thank you so much, Dr. Jaroslaw M Necki
Jaroslaw M Necki very helpful, however, how do you control the pressure inside the Tedlar bag?
Jaroslaw M Necki
AGH University of Science and Technology in Kraków
You do not. You count the volume. You can use syringes or flow controller.
Then we can't actually know the number of moles of N2 inside the Teldar bag, can we? So we can't calculate the concentration in ppm...
Jaroslaw M Necki
AGH University of Science and Technology in Kraków
Julen Lur
, yes we can. In Tedlar bag you will have exactly what you will fill in. If you fill small amount of liquid or gas and than fill a lot of nitrogen than you exactly know what is the mole fraction inside.
Now, important part. You will use large syringe (like 500ml SGE), you will just calculate the amount of gas in reference to atmospheric pressure and lab temperature. If You want to be very precise, use precise measurement pressure gauge and try to keep everything in thermal equilibrium. Hope it is clear now.
Alternatively, you can use precise mass flow controller (MFC) to fill the bag with requested amount of nitrogen, helium or any other gas like zero air. MFC are offered widely. Be careful with any dead or unknown volumes behind MFC !
1 Recommendation

Similar questions and discussions

How do I calculate the gas concentration in PPM?
Question
6 answers
  • Kaleem UllahKaleem Ullah
I have asked two times the following question:
I want to calculate the gas concentration, in ppm, in the closed chamber of volume 1025 cm3. I have a cylinder of mixture of NH3 and air with the 10 and 90% ratio respectively. we are flowing this gas mixture to the chamber at flow rate of 100 sccm. Now how can i calculate the NH3 concentration in ppm inside the closed chamber ?
But my seniors and teachers answer it in a different manner I don’t know to which answer I believe, I am bit confused… the answers I got in response of my questions are as:
Hi Kaleem,
the concentration in ppm does not depend on flow rate or volume as long as the chamber has been evacuated before you introduce the mixture of NH3/air. The ppm measure simply says how many µg/g (weight) or molecules per million molecules (molar ratio) of NH3 there are in the mix.
Assuming that your 1:10 mix is calculated in weight, the concentration is 100,000 µg/g or ~170000 molecules/1,000,000 molecules of mix. The latter, higher molecular ratio arises from the fact that the molar mass of NH3 is lower than the average for air, i.e. per unit weight there are more molecules of NH3 than of the gas mix that makes up air.
If your gas mix of 1:10 is in molecules/molecules (partial pressures), the concentration of NH3 is ~59,000 µg/g or 100,000 molecules/1,000,000 molecules of mix.
The 2nd way of calculations of the question (We have a closed chamber having volume 1000 cm3. 1 sccm of pure oxygen was then incorporated in chamber from flow controller. Air is already present in chamber in which oxygen is 20.95%. How we can calculate the concentration of oxygen in ppm in that chamber?):
a) If we suppose that ppm are cm^3/m^3, we can calculate oxygen concentration as:
V(O2)/V(total) = (209.5+x)cm^3/10^-3m^3.
b) If ppm = mg/l:
m(O2)/V(total) = (209.5+x)*32/(Vm*1).
Here x= is volume of oxygen added, x(cm^3)=1*t ((cm^3/min)*min), t(min) is time during which oxygen was added, 32 is molar mass of O2, Vm is molar volume, 1 = 1litre, volume of your chamber.
The 3rd way of calculations :
xA = mA / mtotal
Parts Per Million (ppm) = xA*106
i.e mole fraction of component (XA *106 )
There are other answers even I know that they are not right….… Now tell me the right way which is most accurate to calculate the gas concentration in PPM......Thanx

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