Question
Asked 5th Aug, 2012

Boolean Function simplification

Boolean Function simplification required (to minimum no of literals)!
F=w'x(z'+yz)+y(ww+w'yz)..?

All Answers (2)

Robert Garian
Library of Congress
Joykrishan:
There are two serious limitations to using Boolean algebra
There is no algorithm you can follow that is guaranteed to lead to the simplest form of the expression
Given any intermediate result there is no way to tell if it is in fact the simplest form of the expression
That doesn't mean that you can't simplify expressions, only that you can't be
sure that you have always found the minimal expression. This is a subproblem of
term rewriting.
for more information on minimization of formulas with up to thousands of variables.
Vipin Musale
Eritrea Institute of Technology
F=w'x(z'+yz)+y(ww+w'yz)
=w'xz'+w'yz+yww+yw'yz
=w'xz'+w'yz+yw+w'yyz
=w'xz'+w'yz+yw+w'yz
=w'xz'+w'yz+w'yz+yw
=w'xz'+(w'yz+w'yz)+yw
=w'xz'+w'yz+yw
=w'(xz'+yz)+yw

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