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Choose a sampling frequency of 20 kHz and a duty cycle of 0.80 v o = V in /(1-D) 2 . The input to the DC-DC Boost converter is the output of the battery. The output of the battery is 24 V,so consider Vo = 600 v. Then the load will equal R=V0 2 /P. The system is designed for supplying the load of 15 kw. Therefore per phase power will be kw so R= 72 ohm hence
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In AC circuits, energy is stored temporarily in inductive and capacitive elements, which results in the periodic reversal of the direction of flow of energy between the source and the load. The average power after the completion of one hole cycle of the AC waveform is the real power, and this is the usable energy of the system and is used to do wor...
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